00:01
So here in this question, the total heat transfer rate through the wall is given by q is equals to the heat transfer rate due to convection, which is qc plus the heat transfer rate due to radiation, which is qr plus the heat transfer rate due to solar radiation, which is qs.
00:22
Here the heat transfer rate due to convection is given by the equation qc is equals to h into a into tw minus ta.
00:32
Here h is the convection, heat transfer coefficient, a is the area of the wall, tw is the temperature of wall surface and t is the temperature of ambient air.
00:41
Heat transfer rate due to radiation is given by qr and that is equals to epsilon into a into sigma into tw raised to the power four minus ts raised to the power four, where epsilon is the emissivity of wall surface, sigma is the stepping boltzmann constant and ts is the temperature of the surrounding surface.
01:04
The heat transfer rate due to solar radiation is given by qs and that is equals to alpha into a into i, where alpha is the solar absorptivity of wall surface, i is the solar radiation incident on the surface and i is the solar radiation incident of the surface.
01:21
Now, we can plug the given values in formula qc and qc is equals to eight into 44 minus 40 and that is equals to 32 watt meter square...