The input resistance of a C E amplifier is 333 Ωand the load resistance is 5 k Ω. A change of ba

step 1 Hello students in this question we have given that we have common amplifier common emitter ampli

The input resistance of a C E amplifier is 333 Ωand the load...

The input resistance of a $C E$ amplifier is $333 \Omega$ and the load resistance is $5 \mathrm{k} \Omega$. A change of base current by $15 \mu$ A results in the change of collector current by 1 $\mathrm{mA}$. The voltage gain of the amplifier is
(A) 550
(B) 101
(C) 1001
(D) 501

Key Concepts

Load Resistance

Load resistance is the resistance in the collector circuit that the amplified output voltage appears across. It plays an important role in determining the magnitude of the output voltage swing, and when combined with the transistor's characteristics, it directly affects the overall voltage gain of the circuit.

Input Resistance

Input resistance refers to the effective resistance seen by the signal source at the base of the transistor. It influences how much of the input voltage appears across the transistor's input and is crucial for proper impedance matching and determining the overall voltage gain of the amplifier.

Transistor Current Gain (?)

This is the ratio of the change in collector current to the change in base current in a bipolar junction transistor. It quantifies how effectively the transistor amplifies current and is a fundamental parameter in analyzing and designing transistor-based amplifier circuits.

Voltage Gain in Common-Emitter Amplifiers

The voltage gain in a common-emitter (CE) amplifier is typically determined by the product of the transistor’s current gain and the ratio of the load resistance at the collector to the input resistance at the base. It is a key performance metric in amplifiers, indicating how much the input voltage is amplified at the output, and it inherently includes a phase inversion.

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