Problem

Evaluate $$ \displaystyle \int_2^\infty \frac{1}…

12:57

Problem 55 Hard Difficulty

The integral
$$ \int_0^\infty \frac{1}{\sqrt{x} (1 + x)}\ dx $$
is improper for two reasons: The interval $ [0, \infty) $ is infinite and the integrand has an infinite discontinuity at 0. Evaluate it by expressing it as a sum of improper integrals of Type 2 and Type 1 as follows:
$$ \int_0^\infty \frac{1}{\sqrt{x} (1 + x)}\ dx = \int_0^1 \frac{1}{\sqrt{x} (1 + x)}\ dx + \int_1^\infty \frac{1}{\sqrt{x} (1 + x)}\ dx $$

Answer

$\pi$

Topics

Integration Techniques

Book Cover for Calculus: Early Tra…

Calculus: Early Transcendentals

Chapter 7

Techniques of Integration

Section 8

Improper Integrals

Discussion

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Video Transcript

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Wen Z.

Topics

Integration Techniques

Book Cover for Calculus: Early Tra…

Calculus: Early Transcendentals

Chapter 7

Techniques of Integration

Section 8

Improper Integrals

Top Calculus 2 / BC Educators

Grace H.

Numerade Educator

Anna Marie V.

Campbell University

Caleb E.

Baylor University

Samuel H.

University of Nottingham