00:01
For a zero -order reaction, the rate stays constant.
00:05
Rate is simply equal to the rate constant.
00:09
So if we are to plot rate versus concentration, the rate does not change with concentration, it just stays constant at k.
00:24
Then if we are to plot the concentration versus time, we are going to see a decrease in the concentration as a function of time, a direct decrease, so we will just have a negative slope, where the slope is equal to the negative of the k value.
01:02
Then they want us to derive an expression for the half -life.
01:06
Well, for the half -life, we have the concentration of a, and the half -life is equal to one -half the concentration of a initial.
01:21
So if the equation they gave us is concentration at time t is equal to concentration at time zero minus kt, and at half -life the concentration t is then going to be equal to one -half the initial concentration, that will be set equal to the initial concentration minus kt.
01:49
So if we subtract a -naught from both sides, we get negative one -half initial is equal to negative kt, and then t, which will be the one -half time, is going to be equal to one -half a initial divided by k, or a initial divided by 2k.
02:17
We then need to figure out the time that it takes for the initial concentration to become zero...