Question
The intrinsic magnetic dipole moment of the electron has magnitude $9.3 \times 10^{-24} \mathrm{A} \cdot \mathrm{m}^{2} .$ In other words, the electron acts as though it were a tiny current loop with $N I A=9.3 \times 10^{-24} \mathrm{A} \cdot \mathrm{m}^{2} .$ What is the maximum torque on an electron due to its intrinsic dipole moment in a $1.0-T$ magnetic field?
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Step 1: The torque on a magnetic dipole in a magnetic field is given by the equation $\tau = \mu \times B$, where $\mu$ is the magnetic dipole moment, $B$ is the magnetic field, and $\times$ denotes the cross product. Show more…
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The intrinsic magnetic dipole moment of the electron has magnitude $9.3 \times 10^{-24} \mathrm{A} \cdot \mathrm{m}^{2} .$ What is the maximum torque on an electron due to its intrinsic dipole moment in a $1.0 \mathrm{T}$ magnetic field?
The magnetic dipole moment of the iron atom is about $2.1 \times 10^{-23} \mathrm{A} \cdot \mathrm{m}^{2} .$ (a) Calculate the maximum magnetic dipole moment of a domain consisting of $10^{19}$ iron atoms. (b) What current would have to flow through a single circular loop of wire of diameter $1.0 \mathrm{cm}$ to produce this magnetic dipole moment?
the magnetic dipole moment of the iron atom is about 2 × 10^-23 Am^2. calculate the maximum magnetic dipole moment of a domain consisting of 10^19 iron atoms. what current would have to flow through a single circular loop of wire of diameter 4.1 cm to produce the magnetic dipole moment you calculated
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