Question
The inward and outward electric flux for a closed surface in units of $\mathrm{Nm}^{2} / \mathrm{C}$ are respectively $8 \times 10^{3}$ and $4 \times 10^{3}$. Then the total charge inside the surface is $\ldots \ldots \ldots \ldots . . \mathrm{c}$.(A) $\left[\left(-4 \times 10^{3}\right) / \epsilon_{0}\right]$(B) $-4 \times 10^{3}$(C) $4 \times 10^{3}$(D) $-4 \times 10^{3} \mathrm{E}_{0}$
Step 1
In this case, it is given by: \[\Phi_{\text{net}} = \Phi_{\text{inward}} - \Phi_{\text{outward}} = 8 \times 10^{3} - 4 \times 10^{3} = 4 \times 10^{3} \, \text{Nm}^{2}/\text{C}\] Show more…
Show all steps
Your feedback will help us improve your experience
Khoobchandra Agrawal and 51 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The inward and outward electric flux for a closed surface in units of $\mathrm{N}-\mathrm{m}^{2} /$ coulomb are respectively $8 \times 10^{3}$ and $4 \times 10^{3}$. Then, the total charge inside the surface is (a) $4 \times 10^{3}$ coulomb (b) $-4 \times 10^{3}$ coulomb (c) $-\left(4 \times 10^{3}\right) / \varepsilon_{o}$ coulomb (d) $-4 \times 10^{3} \varepsilon_{o}$ coulomb
. The inward and outward electric flux for a closed surface in units of N-m2 /coulomb are respectively 8 × 103 and 4 × 103 . Then, the total charge inside the surface is
The flux entering and leaving a closed surface are $5 \times 10^{5}$ and $4 \times 10^{5}$ in MKS unit respectively, then the charge inside the surface will be (a) $-886 \times 10^{-7} \mathrm{C}$ (b) $7.86 \times 10^{-7} \mathrm{C}$ (c) $6.85 \times 10^{7} \mathrm{C}$ (d) $6.85 \times 10^{-7} \mathrm{C}$
Electrostatics
Round 1
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD