The iodate ion is reduced by sulfite according to the following reaction:
$$
\mathrm{IO}_{3}^{-}(a q)+3 \mathrm{SO}_{3}^{2-}(a q) \longrightarrow \mathrm{I}^{-}(a q)+3 \mathrm{SO}_{4}^{2-}(a q)
$$
The rate of this reaction is found to be first order in $\mathrm{IO}_{3}^{-}$, first order in $\mathrm{SO}_{3}^{2-}$, and first order in $\mathrm{H}^{+}$.
(a) Write the rate law for the reaction.
(b) By what factor will the rate of the reaction change if the $\mathrm{pH}$ is lowered from 5.00 to $3.50 ?$ Does the reaction proceed more quickly or more slowly at the lower $\mathrm{pH}$ ?
(c) By using the concepts discussed in Section $14.6, \mathrm{ex}-$ plain how the reaction can be pH-dependent even though $\mathrm{H}^{+}$ does not appear in the overall reaction.