The ion-product constant for water is 1.0 ×10^-14 at 25^∘ C and 3.8 ×10^-14 at 40^∘ C. Is the fo

Name: Problem 11, Chapter 15: Chemistry
Uploaded: 2020-07-28T03:06:12-08:00
Duration: 2 min 18 s
Channel: Susan Hallstrom
Description: The ion-product constant for water is 1.0 ×10^-14 at 25^∘ C and 3.8 ×10^-14 at 40^∘ C. Is the forward process H2 O(l) ⇌H^+(a q)+OH^-(a q) endothermic or exothermic?

step 1 For this question, we are going to look at the ion product constant for water at two temperature

Question

The ion-product constant for water is $1.0 \times 10^{-14}$ at $25^{\circ} \mathrm{C}$ and $3.8 \times 10^{-14}$ at $40^{\circ} \mathrm{C}$. Is the forward process $$ \mathrm{H}_2 \mathrm{O}(l) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{OH}^{-}(a q) $$ endothermic or exothermic?

   The ion-product constant for water is $1.0 \times 10^{-14}$ at $25^{\circ} \mathrm{C}$ and $3.8 \times 10^{-14}$ at $40^{\circ} \mathrm{C}$. Is the forward process
$$
\mathrm{H}_2 \mathrm{O}(l) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{OH}^{-}(a q)
$$

endothermic or exothermic?

Chemistry

Raymond Chang, Jason… 14th Edition

Chapter 15, Problem 11

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The ion-product constant for water is $1.0 \times 10^{-14}$ at $25^{\circ} \mathrm{C}$ and $3.8 \times 10^{-14}$ at $40^{\circ} \mathrm{C}$. Is the forward process $$ \mathrm{H}_2 \mathrm{O}(l) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{OH}^{-}(a q) $$ endothermic or exothermic?