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The ion product of $\mathrm{D}_{2} \mathrm{O}$ is $1.35 \times 10^{-15}$ at $25^{\circ} \mathrm{C}$(a) Calculate pD where $\mathrm{pD}=-\log \left[\mathrm{D}^{+}\right] .$ (b) For what values of pD will a solution be acidic in $\mathrm{D}_{2} \mathrm{O}$ ? (c) Derive a relation between $\mathrm{pD}$ and pOD.

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a. $7 \cdot 43$b. $<7 \cdot 43$c. $14 \cdot 87$

Chemistry 102

Chapter 15

Acids and Bases

Liquids

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03:07

A liquid is a nearly incompressible fluid that conforms to the shape of its container but retains a (nearly) constant volume independent of pressure. As such, a liquid is one of the four fundamental states of matter (the others being solid, gas and plasma). A liquid is made up of tiny vibrating particles of matter, such as atoms, held together by intermolecular bonds. Water is, by far, the most common liquid on Earth. Like a gas, a liquid is able to flow and take the shape of a container. Most liquids resist compression, although others can be compressed. Unlike a gas, a liquid does not disperse to fill every space of a container, and maintains a fairly constant density. A distinctive property of the liquid state is surface tension, leading to wetting phenomena.

04:38

A liquid is a state of matter in which a substance changes its shape easily and takes the form of its container, and in which the substance retains a constant volume independent of pressure. As a result of this, a liquid does not maintain a definite shape, and its volume is variable. The characteristic properties of a liquid are surface tension, viscosity, and capillarity. The liquid state has a definite volume, but it also has a definite surface. The volume is uniform throughout the whole of the liquid. Solids have a fixed shape and a definite volume, but they do not have a definite surface. The volume of a solid does not vary, but the volume of a liquid may vary.

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All right. So we got this imaginary molecule D 20 it's kind of like water. Then we have a I on product, which means you take the ion deep loss times. Well, the concentration of it times the concentration of the O. D negative its other eye on. And it would be that number. They give us 1.35 times 10 to the negative 15 so we can assume that they come out. The the n i N N cat ions come out equally, which means we can represent each of them as X. So X Times ax equals 1.35 times 10 to the negative 15. So let's just rewrite that is X squared and then square take the square, root both sides. Now you've got the kind of situation that you would get from D Tool for either off for both of those ions. But we're gonna use this for our d plus concentration because we need that. For the first part of this question. It's a letter. A what is the p. D? It's his PD instead of ph. So negative log of the D plus concentration, which we just found 3.7 times, sending the negative eight. So if you plug that in, you'll get a number that you can round to 7.43 So that's the answer for a and then be So what is acidic? Well, it would have to be some anything less in 7.43 which means any concentration higher than 3.7 times 10 to the negative eight is this is ah, 7.43 Must be the neutral um P D. So that's what acidic is it for this imaginary molecule? Okay, And then finally see, we want toe come for the relationship between PD and P o. D. So let's get it by taking the negative log of the total concentrations 1.35 times some of the negative 15. If you do that, you get this number 14.87 So that's the, um we're getting that from the deep plus times the OD negative concentrations. So in if we take PD plus p o d. That should always end up being 14.87 and in this case, it was sent, like 7.43 plus 7.43 Um, close enough 14.86 But yet so there you go A, B, C and D

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