00:01
In this problem, we're asked to do a kulom's law calculation.
00:05
We're given the following information.
00:07
The ionic compound, ionic compound, calcium oxide, crystallizes with the same structure as sodium chloride.
00:34
There is a diagram in your text.
00:36
If you're watching this, you have a text reference, and what i'm looking at says it is figure 8 .3.
00:43
And in this structure, it's going to ask us how many 02s, excuse me, o2 minuses, are in contact with each calcium ion.
01:13
And if you can examine this, i decided not to pull this up here.
01:16
But you'll see that each one of these, i'm going to draw what would be the o2 here.
01:24
This will be my o2.
01:26
That's red.
01:28
And it is going to be, what have i got here, calcium? let's just make calcium a very different color.
01:34
How about gold, top, bottom, left, right, front.
01:47
Back.
01:49
I am a terrible artist.
02:00
So that would be the structure that we're going to have.
02:03
Six is the coordination number for sodium chloride.
02:21
And since we're specifically told that the c .a .o.
02:24
As this crystallizes with the same structure, the answer would be six.
02:32
Part b says would the energy be consumed or released? if a crystal of calcium oxide was converted to a widely separated c -a -o -ion pair.
02:55
So would energy be consumed or released? would it be an endo or exothermic reaction if a crystal, and that would be a crystal and a crystal lattice, was converted to widely separated, and this is sort of the interesting part on this one, and it didn't ask for specific ions, but it said a c -a -o -ion pair.
03:50
And of course, energy is required, so energy would be consumed in this process.
04:03
Energy is required to break bonds.
04:17
For part c, we're going to use the ionic radii given in figure 7 .8, and i think that's it.
04:43
We're going to calculate the potential energy, calculating potential energy, of a single c -a -o -ion pair.
05:09
Use the magnitude of the electronic charge that's given in the text.
05:12
So equation for this is going to be as follows.
05:24
And the values we have given inside the front cover, we have 8 .99, i believe it was times 10 to the 9th joule meter per coulum.
05:41
And we're going to use 3 .2 times 10 to the minus 19th coolums for our calcium charge.
05:53
We're going to use 3 .2 times 10 to the minus 19th coulums for the 02 minus charge...