A 100-W light bulb is placed in a cylinder equipped with a moveable piston. The light bulb is turned on for 0.015 hour, and the assembly expands from an initial volume of 0.85 L to a final volume of 5.88 L against an external pressure of 1.0 atm. Use the wattage of the light bulb and the time it is on to calculate E in joules (assume that the cylinder and light bulb assembly is the system and assume two significant figures). Calculate w and q.
LP gas burns according to the exothermic reaction:
What mass of LP gas is necessary to heat 1.5 L of water from room temperature (25.0 C) to boiling (100.0 C)? Assume that during heating, 15% of the heat emitted by the LP gas combustion goes to heat the water. The rest is lost as heat to the surroundings.
Use standard enthalpies of formation to calculate the standard change in enthalpy for the melting of ice. (The Hf for H2O(s) is -291.8 kJ>mol.) Use this value to calculate the mass of ice required to cool 355 mL of a beverage from room temperature (25.0 C) to 0.0 C. Assume that the specific heat capacity and
density of the beverage are the same as those of water.
Dry ice is solid carbon dioxide. Instead of melting, solid carbon
dioxide sublimes according to the equation:
When dry ice is added to warm water, heat from the water causes the dry ice to sublime more quickly. The evaporating carbon dioxide produces a dense fog often used to create special effects. In a simple dry ice fog machine, dry ice is added to warm water in a Styrofoam cooler. The dry
ice produces fog until it evaporates away, or until the water gets too cold to sublime the dry ice quickly enough. A small Styrofoam cooler holds 15.0 L of water heated to 85 C. Use standard enthalpies of formation to calculate the change in enthalpy for dry ice sublimation, and calculate the mass of dry ice that should be added to the water so that the dry ice completely sublimes away when the water reaches 25 C. Assume no heat loss to the surroundings. (The Hf for CO2(s) is -427.4 kJ>mol.)
We know that the internal energy off a system is some off its kinetic along with potential energy off all the particles that composed the system. The Indo no energy is this state function. The internal energy value depends on the state off the system. So we are given with the moss off billiard ball. So the mask is equal to 0.17 kilograms On the initial speed in issue will be 4.5 meters per second on the collision speed. Wait a minute on Dhe the collision speed will be 3.8. Medios was second so the expression for kind of taken Oh Gee, is he called who? Half m V square. The final energy off the system e do is equal to zero the initial energy off the system that this e one is equal to kind of take energy which is also equal to half every square. Substituting in the values we have half my deployed by 0.17 on velocities 4.5 square. We have even equals to hunt one point 72 kilogram meter square. Second square on even is equal to 1.72 Jules from that we can find the difference between an OD state that is e to minus. You won. Did you give this? Zero minus 1.72 gives us the difference off energy as negative one point seven. Tow Jules from the given condition, the believe ball loose some off its energy as a heat using K equals half empty square. We can deter mined the kind of take energy as 1.7 to Jules the ball involved in collision. Then we have mass and velocity again. The kind of take energy off the system can be determined as half empty square. This is the second kinetic energy which turns out to be 1.2 poodles. They are two difference between an energy levels which can be determined by formula Kato minus Okay, one that is kind of dick energy off second system minus the kinetic energy of the first system, which gives us the loss off energy as heat is equal to negative 0.5 jewels from the first law of thermodynamics. Voke done is equal to there's a guy in my nest heat bitches minus 1.7 to Jules minus 0.5 jewels. It gives us the vogue done as negative 1.2 jewels