00:01
So we have a meat sample of 1 .2050 grams.
00:03
We're trying to find the percent of protein in the meat sample.
00:06
We know that if we drive out the nitrogen by having ammonia, we can figure out the percent of nitrogen and this, the mass of nitrogen and this.
00:15
And then we know that the percent of nitrogen and protein is about 16 percent, which means there's 16 percent grams of nitrogen and 100 grams of protein.
00:31
And then we can figure out the percent of protein.
00:33
Protein, right, by figure out what this mass is, and then we can figure out how much of percent protein as in the meat sample.
00:42
So to do that, you go through several steps to infuse ammonia into a sulfuric acid, and then you react that with an oh to figure out how much of the sulfuric acid does not react.
00:55
So you get sodium sulfate and water, and you have to balance it.
01:02
So those two here and then we also have a standard that is going to tell us how much of that superior acid reacts with the sodium nitroxide.
01:16
When you subtract those two, this will give you how much excess and this will give you how much you actually should have all the sulfuric acid reacted and subtracting those two will tell you how much in each superic acid actually reacted within h3, which then will tell us how much nitrogen reacted which then we can use to figure out the percent of protein so we do the same here so what we're gonna do is we're gonna try to figure out the moles of sephoric acid in both of them and we're gonna subtract it so let's start with this one so remember that to go from milliliters to liters we're going to divide about a thousand we have 0 .03 2 to 4 liters of studying my then i do all my units first, liters of sodium hydroxide, two moles of sodium hydroxide, moles of sodium hydroxide, two moles of sulfuric acid.
02:24
Moles to molecules, use your coefficients.
02:27
This is one sepurec acid for every two sodium hydroxides.
02:30
In multi -leaders, you're going to use molarity, which is most per liters.
02:34
So this is 0 .4498 moles in one liter.
02:40
Liters of sodium hydroxide cancel, moles of sodium hydroxide cancel, giving you moles of a sulfuric acid, which is equal to 0 .007251 to 4 -6 -5s, moles of h2s -o4.
02:56
And then we're going to do the standard.
02:58
So what this is, is this is the moles of suphoric acid that did not react within h3, because they reacted with the sodium hydroxide.
03:05
What the standard is going to tell us is how many, if none of the sulfuric acid reacted with an h3, how many moles of a superic acid would we have? now, the only thing that i want you really notice is that the volumes are different.
03:18
So we're going to have to do an extra step at the end to make sure that the moles are comparable in the same size container.
03:25
And i'm going to show you how to do that in a second.
03:26
So 0, let's convert first to moles.
03:29
So 2 to 4 liters of sodium hydroxide, 2 liters to sodium hydroxide, 2 moles of sodium hydroxide, moles of sodium hydroxide, to moles of sulfuric acid and then to get the volumes to be for you to be able to compare the moles that have to be in the same volume so we're gonna take the volume of what we have in this titration and then compare it to the volume of what the other titration is and then millators cancel and then we do for every one more spheric acid you have two moles of sodium hydroxide and then most liters is your concentration which is 0 .4498 moles and 1 liter.
04:26
Leter is the sodium hydroxate cancel, moles of sodium hydroxide cancel, and it gives you moles of sulfuric acid.
04:32
So you have 0 .01 and then 4 -6 -figgs, that's 2, 3, 4 moles of sulfuric acid.
04:40
So this is all the moles of sulfuric acid that you have, right? this is how much of it reacted with sodium hydroxide.
04:47
We're going to figure out how much reactive with n.
04:49
H3...