0 \, \mathrm{A} \cdot \mathrm{h}$ (ampere-hours). We need to convert this to coulombs. We know that $1 \, \mathrm{A} = 1 \, \mathrm{C/s}$ and $1 \, \mathrm{h} = 3600 \, \mathrm{s}$. Therefore, we can write $180.0 \, \mathrm{A} \cdot \mathrm{h} = 180.0 \,
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