00:01
Let mc be the mass of the rocket case and mp is the mass of the payload.
00:11
At first they are traveling together with the velocity v.
00:15
After the clamp is released, a mass c has the velocity vc and a mass p has got the velocity of vp.
00:27
Now we can write a conservation of momentum equation, that is mass c plus mass p together with velocity v is equal to mass c vc plus mpvp.
00:47
Part a of the problem.
00:49
After the clump is released, the payload has a lesser mass and that will be traveling at a greater speed.
00:56
So vp will be we c plus v relative velocity.
01:03
When the expression is substituted, this expression is substituted in above equation for vp, so here, then our resultant equation will come mc plus mp into v is equal to mc vc vc plus mp vc plus mp.
01:26
Then we can from here solve for vc, which is the speed of the case of the rocket, which becomes a vc will become mc plus mp into v minus mp, v relative velocity divided by mc plus mp.
01:53
We'll substitute the values given from the problem, that is 290 plus 150 into 7600 meter per second minus 150 times 910 divided by this whole divided by sum of two masses which is 290 plus 150.
02:16
This gives us a vc of 7290 meter per second...