The lattice energy of $\mathrm{NaCl}$ is $-786 \mathrm{kJ} / \mathrm{mol}$, and the enthalpy of hydration of 1 mole of gaseous $\mathrm{Na}^{+}$ and 1 mole of gaseous $\mathrm{Cl}^{-}$ ions is $-783 \mathrm{kJ} / \mathrm{mol} .$ Calculate the enthalpy of solution per mole of solid NaCl.