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The LD $_{50}$ for saccharin, $\mathrm{C}_{7} \mathrm{H}_{5} \mathrm{NO}_{3} \mathrm{S}$ , is 14.2 $\mathrm{g} / \mathrm{kg} .$ If you have 1 $\mathrm{mol}$ of aspartame and1 $\mathrm{mol}$ of saccharin, which would be more toxic? Show your work.

LD50 for asartame $=10 \mathrm{g} / \mathrm{kg}=0.0339$ moles/kg$\mathrm{LD} 50$ for Saccharin $=14.2 \mathrm{g} / \mathrm{kg}=0.0775 \mathrm{moles} / \mathrm{kg}$

Chemistry 101

Chapter 14

Measuring Toxins

Section 6

Comparing Amounts

Atoms, Molecules and Ions

Composition

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this question is very interesting. Question number four that asks us to determine what is mawr lethal. A mole of saccharine with a lethal dose of 14.2 g per kilogram or a mole of aspartame with a lethal dose of 10 g per kilogram. In order to answer this question, we need to figure out the math that the individual needs to have in order to be able to reach the lethal dose with a mole of saccharine and a mole of aspartame. So we'll start with recognizing that a mole of aspartame is 294.3 g, and a mole of saccharine is 183.18 g. The lethal doses 10 g per kilogram for aspartame and 14.2 g per kilogram poor for Sacramone. So if I have 294.3 g of Asper, Tain and I used, this is a conversion factor. I can now calculate the kilogram mass that will result in the lethal dose. 29.4 kg person would receive the lethal dose, and anybody less than that mass would receive the lethal dose. In the case of saccharine I have 183.18 g when I have one mole. It's lethal doses 14.2 g. So it would, um, kill a person that has a mass of 12.9 g or less. Because the smaller mass, um person results from saccharine than saccharin is more lethal.

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