00:01
So this problem can get a little messy number 83, but it's not too bad if you take it one step at a time.
00:05
So our original rectangle is w for width, 6 plus w for length, and that's going to have an original perimeter of 2w plus 2 times 2 times 6 plus w equals p for perimeter.
00:24
So just so that way we're kind of keeping things a little bit one thing at a time and keeping things organized.
00:31
I'm going to go ahead and simplify now just so that way it's not as weird looking later.
00:36
So i have two to plus 12 plus 2 .w equals the perimeter, which we will eventually be able to figure out the width and all that stuff eventually here in a minute.
00:49
So this simplifies to 4w plus 12 equals perimeter.
00:55
So i was able to get that based off of just the fact that there's a w width and a 6 plus w as our length.
01:02
Then we have to talk about the new stuff.
01:05
What happens if the width is increased by 10? so this w got increased by 10, that's the new width.
01:12
And then our new length, the 6 plus w, got tripled.
01:15
Means we multiply by three.
01:19
And we were given the information that the perimeter here, the new perimeter here, was 56 more than this perimeter that's over here on the original.
01:30
So we're going to have to get this one set up...