00:01
So in this problem, we're told that we have a picture that's in the shape of a rectangle.
00:04
And we're told that the length of this rectangle is 5 inches more than twice its width.
00:11
We also know the perimeter is 112 inches.
00:14
We want to find the dimensions.
00:16
So if i draw a rectangle to represent my picture, what don't we know anything about in this case? well, we know nothing about the width.
00:25
So i'm going to call the width w.
00:27
Well, they told us that the length is 5 inches more than twice the width.
00:34
Well, twice the width would mean two times it.
00:37
So if i need to represent 5 inches more than twice the width, that would mean i need to multiply my width by 2 and then add 5.
00:46
So that would mean the length is 2w plus 5.
00:50
Well, now that i have expressions for the length and the width, and i know the perimeter, i can use the perimeter formula to solve for w.
00:59
Well, remember, the perimeter formula is p equals 2l plus 2w.
01:05
So in this case, we know the perimeter is 112, and that's going to be equal to 2 times the length, which we said was 2w plus 5, plus 2 times the width, which we're calling w.
01:21
And we simply need to solve this equation for w.
01:24
So the first thing we're going to do is distribute the 2 .2.
01:27
2 to both terms in the parentheses...