Question
The length of the seconds hand of a watch is $10 \mathrm{~mm}$. What is the change in atafter 15 seconds(a) Zero(b) $(10 \pi / 2) \mathrm{mms}^{-1}$(c) $(20 / \pi) \mathrm{mms}^{-1}$(d) $10 \sqrt{2} \mathrm{mms}^{-1}$
Step 1
This is because the second hand completes a full circle, which is $2\pi$ radians, every 60 seconds. Show more…
Show all steps
Your feedback will help us improve your experience
Varsha Aggarwal and 73 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The length of second's hand in a watch is $1 \mathrm{~cm}$. The change in velocity of its tip in $15 \mathrm{~s}$ is (a) zero (b) $\frac{\pi}{30 \sqrt{2}} \mathrm{~cm} / \mathrm{s}$ (c) $\frac{\pi}{30} \mathrm{~cm} / \mathrm{s}$ (d) $\frac{\pi \sqrt{2}}{30} \mathrm{~cm} / \mathrm{s}$
Circular Motion
Round 1
The wrench starts at rests and is accelerating at 2 m/s^2 while you throw it, at a given time you notice it has a velocity of 10 m/s, how long was it accelerating for? Group of answer choices a. 2 seconds b. 4 seconds c. 5 seconds d. 10 seconds e. 15 seconds
Select the correct alternative from the given choices. There are two clocks on a wall, both set to show the correct time at $5: 00$ p.m. The clocks lose 2 minutes and 3 minutes respectively in an hour. When the clock which loses 2 minutes in one hour shows $9: 50$ p.m. on the same day, then what time does the other clock show? (A) $9: 30$ p.m. (B) $9: 40$ p.m. (C) $9: 45$ p.m. (D) $10: 15$ p.m.
Reasoning
Clocks and Calenders
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD