00:01
Jumping right into problem 16 here in chapter 1, section 5.
00:03
All right.
00:06
We're told it to find the lengths of a right angled triangle.
00:11
So let's draw a right angled triangle.
00:18
Close enough for government work here.
00:20
All right.
00:23
And we know they're positive.
00:26
The integers are positive.
00:27
Intures that are in succession.
00:29
So this would be one, two, and three that's in succession.
00:35
So we don't know what the smallest side is, but the small side is x.
00:39
And the next side is going to be in succession.
00:42
And this would be the next largest size.
00:44
So it would be plus one.
00:47
And the hypotenuse, which is longer than either of them, would be x plus, but not one.
00:56
It's the next one.
00:57
It's third.
00:57
And if you subtract one from three, you get two.
00:59
So we've got two right here.
01:03
And the hint was to use pythagrin theorem, and pythagrin theorem is a.
01:07
Squared plus b squared equals c squared which is the hypotenuse.
01:14
All right, so writing this out, we can do x for our a a x squared plus our next leg of the triangle, which is x plus one and that squared equals our x plus two squared.
01:35
All right, so let's foil these.
01:40
So for x plus 1, we get times x plus 1, we're going to get first, which is x squared, and then outer and inner, x plus x is plus 2x.
02:03
Adding 2x is together is plus 2x.
02:06
And then last, which is 1 times 1.
02:12
So plus 1.
02:14
All right, now to foil out our x plus 2 times plus 2, we once again go for the first, which is x squared, and then inner and outer, or outer and inner, which is x times 2 and 2 times x.
02:42
So 2x plus 2x is 4x, so plus 4x.
02:47
And then last, which is 2 times 2, which is plus 4.
02:53
All right.
02:54
So adding this to this, we get 2x squared plus 2x plus 1 equals x squared plus 4x plus 4.
03:19
All right...