The level of water in an Olympic-size swimming pool (50.0 m long, 25.0 m wide, and about 2 m

step 1 In approaching to solve this problem, we first need to know the volume of water in liters that i

The level of water in an Olympic-size swimming pool (50.0 m ...

The level of water in an Olympic-size swimming pool $(50.0 \mathrm{m} \text { long, } 25.0 \mathrm{m} \text { wide, and about } 2 \mathrm{m}$ deep ) needs to be lowered $3.0 \mathrm{cm} .$ If water is pumped out at a rate of $5.2 \mathrm{L}$ per second, how long will it take to lower the water level $3.0 \mathrm{cm} ?$

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Key Concepts

Unit Conversion

Unit conversion is the process of converting measurements from one unit to another to maintain consistency in calculations. In this problem, it involves converting centimeters to meters for the water level change and liters to cubic meters for the rate of water removal. Accurate conversion ensures that all quantities are expressed in compatible units, which is essential for correct computation of volume and time.

Volume Calculation

Volume calculation for a rectangular prism, such as a swimming pool, involves multiplying the area of the base by the height. Here, the change in the water level (height) multiplied by the surface area of the pool gives the volume of water removed. This concept is fundamental in understanding how dimensional changes affect overall volume.

Rate and Time Relationship

The rate and time relationship describes how the rate at which work is done (or in this case, water is pumped) relates to the total amount of work done (total volume of water removed). It is expressed by the formula: time equals volume divided by the pumping rate. This relationship is crucial in determining the duration required to achieve a specific volumetric change.

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