Question
The light beam in Figure $\mathrm{P} 25.53$ strikes surface 2 at the critical angle. Determine the angle of incidence $\theta_{1}$
Step 1
We can use the critical angle of 42 degrees to find the ratio $n_2/n_1$. Using Snell's law, we have $n_2 \sin(42^{\circ}) = n_1 \sin(90^{\circ})$. This simplifies to $n_2/n_1 = 1/\sin(42^{\circ}) = 1.409$. Show more…
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