Question
The light emitted from one of the following electronic transitions $(n=4 \longrightarrow n=3$ or $n=3 \longrightarrow n=2)$ in the hydrogen atom causes the photoelectric effect in a particular metal, whilelight from the other transition does not. Which transition causes the photoelectric effect and why?
Step 1
6 \left( \frac{1}{n_{i}^{2}} - \frac{1}{n_{f}^{2}} \right) eV\] where \(E\) is the energy of the photon, \(n_{i}\) is the initial energy level, \(n_{f}\) is the final energy level, and \(13.6 eV\) is the ionization energy of hydrogen. Show more…
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The light emitted from one of the following electronic transitions (n = 4 - n = 3 or n = 3 - n = 2) in the hydrogen atom causes the photoelectric effect in a particular metal while light from the other transition does not. Which transition causes the photoelectric effect and why?
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