The lines of the rotational spectrum of $\mathrm{HBr}$ are $5.10 \times 10 \times \mathrm{Hz}$ apart in frequency. Find the internuclear distance in $\mathrm{HBr}$. (Note:
Since the $\mathrm{Br}$ atom is about 80 times more massive than the proton, the reduced mass of an HBr molecule can be taken as just the ${ }^{1} \mathrm{H}$ mass.