00:01
We have been given in the following questions and assertion is followed by a reason.
00:04
Mark your responses from the following options.
00:06
So we have been given an assertion and a reason.
00:09
So let us work out the problem.
00:13
So in this question we have f of x equal to limit n tends to infinity, cos pi x minus x to the power of 2n, sign of x minus, 1 whole upon 1 plus x to the power of 2n plus 1 minus x to the power of 2n.
00:49
So that means f of x is equal to cos pi x minus 0 upon 1 plus x minus 0 for mod x equal to 1.
01:11
So this is equal to cost pi x minus sine of x minus 1 whole upon 1 plus 1 minus 1.
01:32
So therefore, i think it made a small issue error.
01:37
This would be for mod x less than 1.
01:39
This would be for mod x equal to 1.
01:48
Yeah...