00:01
Hey, greetings.
00:03
For this problem, we get to do a little algebra with our lorentz transformations.
00:08
So here are the lorentz transformations right here and our definition for gamma.
00:18
The problem says if we put, if we have t equals t -prong, then what are our values for x and x -prong? so what i've done is if i have t equals t prime then i this first equation up here i just make t prime into t and then i substitute this value i solve this equation for t right here and then i substitute this value for t into this equation so when to do that i have this guy right here so if i rearrange that equation a little bit i have pull pull my xes out and pit the gamma in and i grab this c squared and put it on top and now i've got 2v so i've got v squared every c squared so i have this guy right here and i'm going to find a light denominator so i'm going to multiply this this term by one gamma minus 1 over gamma minus 1 so now i have a light denominator and i'm going to multiply this gamma right and i'm going to multiply this right here into the parentheses and get, so i'm going to get gamma squared minus gamma and i still have that third term right here.
01:52
This right here, i'm just rearranging the terms on top.
01:55
I'm basically pulling these gamma squares together and then i'm going to pull them out right here.
02:03
So in parentheses i have, from here i have the one and from here i have the v squared over c squared.
02:12
So this term right here, this line right here just shows you that that term is in fact just equal to 1.
02:23
Because gamma here's my definition of gamma square and it's basically the inverse of this term right here...