00:01
We're given quite a bit of information and the equation that we're looking at is right here.
00:08
Okay, we are told that our slow step is, and our fast step is, okay, so let's predict the rate law based on our reaction mechanisms.
01:50
So i'm going to say that the rate law will be first order, k times, i'm just going to write trans.
02:28
Okay, that's what i'll say will be my rate law for the first one.
02:45
There we go.
02:47
And for b, as the reaction proceeds, blah, blah, blah, blah, blah, color changes from green to red with a gray intermediate stage.
03:30
The gray color is reached at the same time, no matter what concentrations initially.
04:02
How does this show the reaction is first order? if it was zero order, let me see, if it were zero order, then it would take a longer time for the gray intermediate to form.
05:25
So it's not zero order.
05:27
If it was second order, the rate would be dependent on the square of the concentration.
05:53
This is not true.
05:59
So that justifies the first order classification.
06:15
Okay, then c, we have to plot, plot the ln of k versus one over t.
06:34
And k equals negative one over t times the ln of r over r zero.
06:57
The time is a measure of k, use the data below.
07:02
So we have data, temp in degrees c is 56, 60, 65, and 70.
07:12
Then i'm going to go over here, the time is 156.
07:18
This is all in seconds, 114, 88, and 47.
07:28
Okay, so we're going to add 273 and one over x...