Question
The lower end of a capillary tube of radius $r$ is placed vertically in water. Then with the rise of water in the capillary, heat evolved is(a) $+\frac{\pi^{2} r^{2} h^{2}}{J} d g$(b) $+\frac{\pi r^{2} h^{2} d g}{2 J}$(c) $-\frac{\pi r^{2} h^{2} d g}{2 J}$(d) $-\frac{\pi r^{2} h^{2} d g}{J}$
Step 1
Step 1: The force due to surface tension is given by $F = 2\pi rT\cos\theta$, where $T$ is the surface tension, $r$ is the radius of the capillary tube, and $\theta$ is the contact angle. Show more…
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