00:01
We're asked to answer a question about the mock number using multiple angle and product to some formulas.
00:08
We're told the mock number m of a supersonic airplane is the ratio of its speed to the speed of sound.
00:15
When an airplane travels faster than the speed of sound, the sound waves form a cone behind the airplane.
00:22
The mock number is related to the apex angle theta of the cone by sine of theta over 2 equals 1 over in part a, we're asked to use a half -angle formula to rewrite the equation in terms of cosine of theta.
00:43
Well, let's use the half -angle identity on the left -hand side.
00:51
This is equal to plus or minus the square root of 1 minus the cosine of theta over 2 equals 1 over m.
01:04
So now we want to solve this for cosine of theta.
01:09
To do this, we have a radical equation, so i'll square both.
01:12
Sides, we get 1 minus the cosine of theta over 2 equals 1 over m squared.
01:20
Therefore, 1 minus cosine of theta equals 2 over m squared, and therefore, cosine of theta equals 1 minus 2 over m squared.
01:34
Which is equal to m squared minus 2 over m squared.
01:44
Then in part b, we're asked to find the angle theta that corresponds to a model.
01:49
Number of 1.
01:55
In other words, want to find the value of theta, such that cosine of theta equals 1 squared minus 2 over 1 squared.
02:05
So this is negative 1.
02:10
For a cosine of theta to be equal to negative 1, this implies that theta must be equal to pi.
02:25
In part c, we're asked to find the angle theta that corresponds to a mock number of 4 .5.
02:30
In other words, so the cosine of theta is equal to 4 .5 squared minus 2 over 4 .5 squared.
02:39
Well, 4 .5 is the same as 9 halves...