Question
The magnetic field at a distance $r$ from a magnetic dipole $\mu$ is $B=\mu_{0} \mu / 2 \pi r^{3} .$ Show that the dipole-dipole interaction energy is too small to account for the ferromagnetism of iron at all but the lowest temperatures. Assume an effective magnetic dipole moment of $2.2 \mu_{\mathrm{B}}$ per atom.
Step 1
The formula for this is given by $U = B\mu$, where $B$ is the magnetic field and $\mu$ is the magnetic dipole moment. Substituting the given expression for $B$ into this formula, we get: \[U = \frac{\mu_{0} \mu^{2}}{2 \pi r^{3}}\] Show more…
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Magnetostatics
Round 2
When a magnetic dipole is placed in a magnetic field, it has a natural tendency to minimize its potential energy by aligning itself with the field. If there is sufficient thermal energy present, however, the dipole may rotate so that it is no longer aligned with the field. Using $k_{\mathrm{B}} T$ as a measure of the thermal energy, where $k_{B}$ is Boltzmann's constant and $T$ is the temperature in kelvins, determine the temperature at which there is sufficient thermal energy to rotate the magnetic dipole associated with a hydrogen atom from an orientation parallel to an applied magnetic field to one that is antiparallel to the applied field. Assume that the strength of the field is $0.15 \mathrm{~T}$.
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