Question
The magnetic field between the plates of a capacitor is given by $B=\frac{\mu_{0} I r}{2 \pi R^{2}}$(A) $r \geq R$(B) $r \leq R$(C) $r<R$(D) $r=R$
Step 1
Step 1: According to Ampere's law, the magnetic field inside a solenoid is given by $B=\frac{\mu_{0} I}{2 \pi R}$, where $\mu_{0}$ is the permeability of free space, $I$ is the current, and $R$ is the radius of the solenoid. Show more…
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A parallel-plate capacitor consists of circular plates of radius R, separated by a small distance d. The capacitor is connected to an AC emf such that the electric field between the plates oscillates as: E(t) = Eo*sin(ωt). What is the induced magnetic field inside (r < R) and outside (r > R) the capacitor? Assume the electric field is uniform inside the capacitor and ignore any fringe electric fields at the edges.
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