The magnetic field in a cyclotron is 0.50 T. Find the magnitude of the magnetic force on a prot

Name: Problem 18, Chapter 19: College Physics
Uploaded: 2021-08-17T15:42:39-08:00
Duration: 1 min 38 s
Channel: Vishal Gupta
Description: The magnetic field in a cyclotron is 0.50 T. Find the magnitude of the magnetic force on a proton with velocity of 1.0 ×10^7 m / s in a plane perpendicular to the field.

step 1 in this given problem in cyclotron the magnetic field is having a magnitude of 0 .50 Tesla and v

Question

The magnetic field in a cyclotron is $0.50 \mathrm{~T}$. Find the magnitude of the magnetic force on a proton with velocity of $1.0 \times 10^{7} \mathrm{~m} / \mathrm{s}$ in a plane perpendicular to the field.

   The magnetic field in a cyclotron is $0.50 \mathrm{~T}$. Find the magnitude of the magnetic force on a proton with velocity of $1.0 \times 10^{7} \mathrm{~m} / \mathrm{s}$ in a plane perpendicular to the field.

College Physics

lan Giambattista,… 2nd Edition

Chapter 19, Problem 18

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Solved by Expert Vishal Gupta

08/17/2021

Step 1

Step 1: The magnetic force experienced by a charged particle moving in a magnetic field is given by the equation: \[ F = qvB\sin\theta \] where $ F $ is the magnetic force, $ q $ is the charge of the particle, $ v $ is the velocity of the particle, $ B $ Show more…

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The magnetic field in a cyclotron is $0.50 \mathrm{~T}$. Find the magnitude of the magnetic force on a proton with velocity of $1.0 \times 10^{7} \mathrm{~m} / \mathrm{s}$ in a plane perpendicular to the field.

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Key Concepts

Lorentz Force

The Lorentz force is the net force experienced by a charged particle moving in electric and magnetic fields. In the context of a magnetic field only, it is given by the cross product F = q(v × B), where q is the charge of the particle, v is its velocity, and B is the magnetic field. This formula illustrates that the force is perpendicular to both the velocity of the particle and the magnetic field direction.

Magnetic Force on Moving Charges

When a charged particle moves in a magnetic field, it experiences a force whose magnitude is given by F = qvB sin?, where ? is the angle between the particle’s velocity and the magnetic field. For motion in a plane perpendicular to the field, sin? equals 1, which simplifies the calculation of the force. This concept is fundamental in understanding the behavior of particles in devices like cyclotrons and other particle accelerators.

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