The magnetic field of the Earth can be approximated as the magnetic field of a dipole, with horizontal and vertical components, at a point a distance $r$ from the Earth's center, given by
$$
B_{h}=\frac{\mu_{0} \mu}{4 \pi r^{3}} \cos \lambda_{m}, \quad B_{v}=\frac{\mu_{0} \mu}{2 \pi r^{3}} \sin \lambda_{m},
$$
where $\lambda_{m}$ is the magnetic latitude (this type of latitude is measured from the geomagnetic equator toward the north or south geomagnetic pole). Assume that the Earth's magnetic dipole moment is $\mu=8.00 \times 10^{22} \mathrm{~A} \cdot \mathrm{m}^{2} .$ (a) Show that the magnitude of the Earth's field at latitude $\lambda_{m}$ is given by
$$
B=\frac{\mu_{0} \mu}{4 \pi r^{3}} \sqrt{1+3 \sin ^{2} \lambda_{m}}
$$
(b) Show that the inclination $\phi_{i}$ of the magnetic field is related to the magnetic latitude $\lambda_{m}$ by
$$
\tan \phi_{i}=2 \tan \lambda_{m}
$$