The magnetic moment of the Earth is approximately $8.00 \times 10^{22} \mathrm{A} \cdot \mathrm{m}^{2} .$ Imagine that the planetary magnetic field were caused by the complete magnetization of a huge iron deposit with density 7900 $\mathrm{kg} / \mathrm{m}^{3}$ and approximately 8.50 $\times 10^{28}$ iron atoms/m^{3} . (a) How many unpaired electrons, each with a magnetic moment of 9.27 $\times 10^{-24} \mathrm{A} \cdot \mathrm{m}^{2}$ , would participate? (b) At two unpaired electrons per iron atom, how many kilograms of iron would be present in the deposit?