00:01
In this example, we are trying to find the maximum magnetic force on an electron moving near the earth's surface.
00:07
So we've got a magnetic field of about 0 .5 ghosts, and we are given a kinetic energy of one kilo -electron volt.
00:15
So we can first write out the equation for the magnetic force, fb.
00:23
And if we assume that, well, first we can write equal to qb cross b.
00:31
But if the electron's moving really close to the earth, it'll be pretty much perpendicular, so the cross product can go away, and this will just become qvb.
00:42
And then we are given a kinetic energy of one kilo -electron volt, which, if you change that into joules, that is approximately 1 .6 times 10 to the minus 16 joules.
01:09
And we know another form of kinetic energy.
01:13
Well, okay, so if we're looking at the magnetic field, we notice that the first thing we need to find to get this for us is we have q and we have b, but we still need to find b.
01:24
So we're given this kinetic energy, and we can set this equal to 1 .5 mv squared, which is a form of kinetic energy.
01:37
And from this, we can find the velocity and put that into the magnetic field force equation.
01:43
So we put, you have the kinetic energy equal to this.
01:52
And if we rearrange this in terms of v, we get b is equal to square root of 2 times kinetic energy, 1 .6 times 10 to minus 16.
02:09
And this divided by the mass of the electron, which is 9 .11 times 10 to minus 31 kilograms.
02:21
We take that square root, we get a velocity equal to 1 .9 times 10 to the 7 meters per second...