Question
The magnitude of electric intensity at a distance $x$ from a charge $q$ is $E$. An identical charge is placed at a distance $2 x$ from it. Then the magnitude of the force it experiences is(A) $q E$(B) $2 q E$(C) $\frac{q E}{2}$(D) $\frac{q E}{4}$
Step 1
Step 1: The electric field intensity at a distance $x$ from a charge $q$ is given by Coulomb's law as $E = \frac{kq}{x^2}$, where $k$ is Coulomb's constant. Show more…
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