Question
The magnitude of the displacement of the particle at time $\mathrm{t}=6 \mathrm{~s}$ is(a) $12 \mathrm{~cm}$(b) $36 \mathrm{~cm}$(c) $24 \mathrm{~cm}$(d) $6 \mathrm{~cm}$
Step 1
Step 1: The given equation of velocity is $v = u + a t$, where $u$ is the initial velocity, $a$ is the acceleration, and $t$ is the time. Show more…
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A particle of mass $m$ moving in one dimension whose displacement is $x$ under the action of a force, isrelated to time $t$ (in sec) by $t=\sqrt[3]{x}+6$. The displacement of the particle when its velocity is zero, will be: (a) $2 \mathrm{~m}$ (b) $4 \mathrm{~m}$ (c) $0 \mathrm{~m}$ (d) $6 \mathrm{~m}$
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