00 kg. We know that the molar mass of $\mathrm{Na}_{3} \mathrm{AlF}_{6}$ is 209.94 g/mol. Therefore, the number of moles is given by the mass divided by the molar mass. In this case, it is $\frac{1000 \, \text{g}}{209.94 \, \text{g/mol}} = 4.76 \, \text{mol}$.
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