00:01
So we're going to have a 1 % significance test to determine if reducing the price seems to increase sales.
00:08
So we'll have group one will be the regular price and group two will be the reduced sale 10 % off.
00:16
And they want to see does that reduction cause an increase.
00:19
So we have more sales with that second group that is reduced.
00:23
And we have some sales figures and we have from our first group had a sample size of, of seven.
00:32
And our second group had a sample size for the reduced value of eight.
00:35
And we had a mean for the first group.
00:38
The mean sales for the first group was 117 .714 with a sample standard deviation of 19 .914.
00:48
And for our second group, they had a mean sales of 125 .125.
00:55
And the sample standard deviation was 15 .094.
01:03
Now, we will be doing a two sample t test due to the fact that we have small sample sizes that are less than 30, and we don't know that these populations are normal.
01:16
So we'll have to use the t test.
01:18
We're also going to be assuming that these two standard deviations are approximately equal, and that causes us to have to find the pooled variance.
01:27
And our pooled variance we'll determine is to take one less than the first sample size times the variance of the first group, and one less than the sample size times the variance of the second group, and then divided by actually our degrees of freedom, which is 7 plus 8 minus 2.
01:46
So that's 15, that's 13.
01:47
So our degrees of freedom will be 13.
01:50
So let's get this calculation and go from there.
01:55
So we have left parenthesis that six times that 19 .914 squared.
02:01
And let me do a little correction there.
02:03
Just hit something wrong.
02:05
Okay, plus the seven times the 15 .094 squared.
02:12
Close off that parentheses and then divided by my 13...