00:01
Question number 42 is asking us to calculate the size of the smallest objects that can be observed by the camera on the mars reconnaissance orbiter.
00:12
Well, in order to solve that problem, it requires the formula for angular resolution.
00:19
But we're going to need to do some rearranging for this formula because we already know the angular resolution.
00:26
It's given to us in the problem.
00:28
And we're going to need to solve for a different part of it.
00:32
So here's the formula for angular resolution.
00:38
2 .06 times 10 to the 5th times lambda over d arc seconds.
00:47
And in the problem, we are given d, that's the distance above mars that the mars reconnaissance orbiter orbits.
00:56
It's 280 kilometers.
01:01
And we're also given our angular resolution.
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That is 0 .2 arc seconds.
01:11
Now, what we need to find is our lambda, our wavelength that we're observing in.
01:19
How does that correlate to the smallest features that can be observed on mars? well, a wavelength is a type of length, and we're being asked to measure the size of the smallest objects that can be observed on mars by the mars reconnaissance orbiter...