Question
The masses of three wires of copper are in the ratio of $1: 3: 5$ and their lengths are in the ratio of $5: 3: 1$. The ratio of their electrical resistance is:(A) $1: 1: 1$(B) $1: 3: 5$(C) $5: 3: 1$(D) $125: 15: 1$
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We denote these ratios as $m_1 : m_2 : m_3$ and $l_1 : l_2 : l_3$ respectively. Show more…
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Masses of three wires of copper are in the ratio of 1 : 3 : 5 and their lengths are in the ratio of 5 : 3 : 1. The ratio of their electrical resistances are (a) 1 : 3 : 5 (b) 5 : 3 : 1 (c) 1 : 15 : 125 (d) 125 : 15 : 1
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