00:01
Hello, so today we'll be looking at possible resonance forms for aluminum iodide, this molecule with this compound right here.
00:12
So let's first count up the valence electrons.
00:16
So aluminum has three valence electrons, iodine has seven, and there are three of them.
00:24
Let's add them up, three times seven is 21, plus three is 24 electrons.
00:32
So let's count up how many need.
00:35
So aluminum needs eight, id needs eight, and there are three of them.
00:41
So that's a total of 32 electrons.
00:46
So if we take how many we need, subtract how many we have and divide by two, that will usually give you how many bonds you need.
00:56
So in this case, four bonds.
00:59
So if you just draw three bonds around aluminum and you just add lone pairs to iodide, you will notice that iodide has complete octats, and if you count out the electrons, 24, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, we have the correct amount of electrons.
01:35
But three bonds isn't enough because aluminum doesn't have a full octet.
01:42
If you look at the formal charges, the formal charges are all zero, but aluminum doesn't have a full octet.
01:51
So what we would do is we would add a bond.
01:57
And now look, we have, now aluminum has a full octet.
02:07
Iodide has full all of the iodines have a full octet as well.
02:12
So this works...