The $\mathrm{pH}$ at the equivalence point when a solution of $0.01 \mathrm{M}-\mathrm{CH}_{3} \mathrm{COOH}$ is titrated with a solution of $0.01 \mathrm{M}-\mathrm{NaOH}$, is $\left(\mathrm{p} K_{\mathrm{a}}\right.$
of $\mathrm{CH}_{3} \mathrm{COOH}=4.7, \log 5=0.7$ )
(a) $10.5$
(b) $3.5$
(c) $10.35$
(d) $3.65$