00:01
Since we have given ph, that is we have 2 .77, with the help of this ph, i can calculate the concentration for h -positive ion.
00:11
So, since ph, so that is the negative logarithm of concentration of h -positive ion, so now putting the values, this can be written as concentration of h -positive iron is equal to, so this is 10 -rate -to -power minus 2 .77.
00:28
Solving this we will have h positive ion concentration is equal to 0 .017 molar.
00:39
Now here we have been given this hocn, okay, so we will consider this dissociation in the water, okay, so it will lead to form aqua solution.
00:51
So, hocn, that is aquaise form now, it dissociates to form, it dissociates to form, h positive ion in aquas form and we have ocn negative in aqueous form okay so now initial so initially we have 0 .01 and we have 0 and 0 okay so that is the initial concentration now equilibrium so we have 0 .0 01 minus x x x okay so that much concentration at equilibrium now k a that is the dissociation constant for this acid so that is find out by the concentration of products divided by reactant concentration that is concentration for h positive and multiplied by a concentration of o cn negative divided by h o cn concentration so now put in the values.
02:21
So ka that's equal to we have h positive ion concentration.
02:28
So now this h positive ion concentration and oc and negative concentration...