00:01
In this problem, we are modeling a living cell by a parallel plate capacitor.
00:05
We're given the separation distance, the dialectic constant, which represents the material between the plates, filling between the plates, the area of one of the plates, and we also are told the potential difference between the plates.
00:19
And our goal is to find out two things.
00:24
The amount of charge that's on one of the plates.
00:26
Remember, one plate has plus q, the other has minus q.
00:30
You can think of the electric field as driving off the other positive charges and leaving a negative.
00:38
I think of a traditional circuit.
00:40
So we'll find the charge, q, and then i'm going to be asked how many ions that makes up that charge.
00:49
Now, let's calculate first the charge.
00:52
Q is equal to c times v.
00:55
Formula for c with a dielectric constant, kappa, epsilon 0a over d.
01:01
And then we've got to multiply this by v to get our q.
01:05
And we can put in everything here.
01:07
This is 5 .8 .85 times 10 to minus 12.
01:16
Kulam squared, newton, meters squared, 5 times 10 to the minus 9 meter squared for the area.
01:31
That's over 1 times 10 to the minus 8 meters.
01:38
And we have the v now to put in 60 millivolts or 60 times 10 and minus 3 volts...