Question
The Michaelis-Menten equation for the enzyme chymotrypsin is$$v=\frac{0.14[\mathrm{S}]}{0.015+[\mathrm{S}]}$$ where $v$ is the rate of an enzymatic reaction and $[\mathrm{S}]$ is the concentration of a substrate S. Calculate $d v / d[\mathrm{S}]$ andinterpret it.
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In this case, it is the Michaelis-Menten equation for the enzyme chymotrypsin, which is given as: $$v=\frac{0.14[\mathrm{S}]}{0.015+[\mathrm{S}]}$$ Show more…
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The Michaelis-Menten equation for the enzyme chymotrypsin is $ v = \frac {0.14[S]}{0.015 + [S]} $ where $ v $ is the rate of an enzymatic reaction and [S] is the concentration of a substrate S. Calculate $ dv/d[S] $ and interpret it.
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The Michaelis-Menten equation for the enzyme chymotrypsin is 0.14[S] / 0.015 [S], where v is the rate of an enzymatic reaction and [S] is the concentration of a substrate S. Calculate dv/d[S] and interpret it.
The Michaelis-Menten equation models the rate $v$ of an enzymatic reaction as a function of the concentration [S] of a substrate S. In the case of the enzyme chymotrypsin the equation is $$ v=\frac{0.14[\mathrm{S}]}{0.015+[\mathrm{S}]} $$ (a) What is the horizontal asymptote of the graph of $v$? What is its significance?$$$$ (b) Use a graphing calculator or computer to graph $v$ as a function of [S].
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