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The middle-C hammer of a piano hits two strings, producing beats of 1.50 $\mathrm{Hz}$ . One of the strings is tuned to 260.00 $\mathrm{Hz}$ . What frequencies could the other string have?
$f_{2,1}=258.5 \mathrm{Hz}$$f_{2,1}=261.5 \mathrm{Hz}$
Physics 101 Mechanics
Physics 103
Chapter 16
Oscillatory Motion and Waves
Periodic Motion
Wave Optics
University of Michigan - Ann Arbor
Simon Fraser University
University of Sheffield
Lectures
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So we know that the frequency of the beets is equaling the frequent frequency of the absolute value of the difference between the frequency of the first instruments and the frequency of the second instrument. We know that the beat has a frequency of 1.50 hurts. This is equaling the absolute value of the frequency of the first instrument that one string of 260 0.0 hurts. And then this would be minus the frequency of the second string. So the other string and so we can say that the frequency we could say frequencies up to the frequency of the second string or the other string could either be 261.50 hurts four, 258.50 hurts. And so either answer would be correct. Rather, both answers are correct. That is the end of the solution. Thank you for watching
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