00:01
So for this problem, we want to know how much silver bromide is produced from the following balance equation, given the starting values given to us in the problem itself.
00:27
This agbr is our silver bromide that we are calculating for in this problem.
00:36
So first we want to find the moles of our first reactant, and then we're going to find moles of our second.
00:57
So in order to do this, we're going to do the molarity times the volume in liters, and we know the molarity to be 0 .15.
01:12
And we are given the volume in milliliters, so we can just divide that by 1 ,000 to get liters.
01:16
Find that to be 0 .1.
01:20
So our number of moles, 0 .015 for our first reactant.
01:32
Now we're going to do the same for the second.
01:38
So we know molarity is 1, and our volume in liters is 0 .02...