the-model-l4-s-gives-the-total-number-of-legs-that-s-sheep-have-using-this-model-we-find-that-12-she

Name: the model l4 s gives the total number of legs that s sheep have using this model we find that 12 she
Uploaded: 2019-06-17
Duration: 1 min 4 s
Channel: Numerade
Description: The model $L=4 S$ gives the total number of legs that $S$ sheep have. Using this model, we find that 12 sheep have $L=$ __________ legs.

Question

The model $L=4 S$ gives the total number of legs that $S$ sheep have. Using this model, we find that 12 sheep have $L=$ __________ legs.

Amy Jiang · Accepted Answer

So we&#x27;re given a model L. A is equal to for us, which gives the total number of legs that as she passed, so s is you go to the number of ships we have. We&#x27;re going to use this model owned vehicle too, or s to figure out how many sheeps. Well, how many leagues? 12. She path. So since we have 12 sheep as you go too 12 And what we basically have to do is we plug in. This s here into here is given model. So it&#x27;s true that you have oh, is equal to four times 12 and that&#x27;s good to 48. So it is 48 legs, 12 ships.

Heather Zimmers · Answer

This is Thies system from the problem where age represents the number of bones in the hand and F represents the number of bones in the foot and they add together to be 53. And there&#x27;s one more bone in the ham. So the difference between the two is one. We&#x27;re going to use this system to figure out the value of H and the value of F notice that we have opposite F terms. So if we go ahead and add these equations together, the F terms will be eliminated and we&#x27;ll have to h equals 54. We can divide that by two, and we get a CI equals 27. So now that we have that, we can use one of our two equations to find the value of F. How about if we use the top one? So we&#x27;ll plug the 27 in for H, and we have 27 plus F equals 53. We can subtract 27 from both sides, and we get f his 26 so that so that tells us 27 bones in the hand. 26 bones in the foot

Tani Iqbal · Answer

Okay, so this is our table for number three. So we&#x27;re going to see how much the graft changes. Um, per increments. So for the X values who for the X values you go up to up to up to, Up to up to. Okay. As for your why values We go up Six of six up, six up, six and six ago. So our first set of changes the consistence in the wise. So that means it&#x27;s going to be linear. Okay, so then so we got to find out the equation y is equal to m explosive e. And, uh, let&#x27;s see. MM is a little bit easier. You take M is the change in why over changing X. And we have that the chain and why it&#x27;s six. And then the change in excess to six over two. It&#x27;s the same thing as three. So then we&#x27;ll have. Why is equal to three X and then we&#x27;ll be there multiple ways to do this. The easiest way is to look at your table. You&#x27;re trying to get to where x zero. So then just go down. But on the inside. So you go down too. A good to zero, and we&#x27;ll go down six, which will get you negative too. Okay, so that negative too. That&#x27;s my B. Okay, So that one matches with P. So that&#x27;s your algebra cancer? No, graphically. So graphically is a little bit different. So I just pulled up the graphs, so it&#x27;s a linear. So look at your linear graph. So we&#x27;re going to George&#x27;s and out of takeout. What, somewhere? What isn&#x27;t linear. Okay, so then just take out everything that looks quadratic or similar. Just keep one&#x27;s okay? And we know what? Could we have a slow boat three? It&#x27;s kind of hard to tell in this graph, so I&#x27;m just going to eliminate the negative slope. And then, uh, our intercept is negative, too. So it&#x27;s gonna be below the, um, X axis, which is not be d goes through the origin. So it&#x27;s going to be either a ir ji. So now it&#x27;s a little bit more iffy because it&#x27;s really hard to tell in the grass. So what I&#x27;m gonna do is figure out that point over here, so wherever wise vehicle to zero, I&#x27;m going to find that x intercept. So where is why gonna be equal to zero. Let&#x27;s see. Why is it called a zero? It&#x27;s going to be the halfway point C. Oh, why is it always the obligatory question? Zero is equal to three X minus two two. You get to is equal to three X and then divide by three. So about 2/3. So that&#x27;s less than one. The access over here G is more than one. So the the X intercept. So then it&#x27;s going to be a So I displayed in points to see what worked for my ex intercept, since we would have our wires.

Naomi Motes · Answer

two times or I am going to model LaMotte. The holds a patient. So I have two groups of four. So I&#x27;m just just gonna draw two groups or two boxes, and I&#x27;m gonna put four in each group, so I have one too. Three or 123 four. So together and all, I have eight.

Tani Iqbal · Answer

Okay, So for this problem, we&#x27;re going to see the change in our excess first, to figure out our elder breaking graphical representation. So then the X is increased by increments of one and the change and why? So 36 39 to 36 is You go down three 36 to 31. You go down five 31 to 24. You go down seven. Then you go down nine and then you go down 11. Okay, so are changes not linear, because none of these numbers are the same. So let&#x27;s look at her change of the change. So then we go down, two down, two down, two don&#x27;t to. Okay, so the change. So the second set of changes is consistent, So this is gonna be a quadratic equation. Okay. Luckily for us, we have answered choices, and this is the only negative quadratic, and that only negative quadratic is found in equation Oh, which is 40. Which is why is equal to 40 minus export. Okay. And same for our graphical representations. If I want a negative graph, it&#x27;s going to have to be upside down. We only have one of those, and that is letter E. So that&#x27;s your answer.

Ankit Gupta · Answer

we have been given the values and these tables are for medicine men&#x27;s US shoe size and makes you a pit crew size. And it has been represented by your function. Dagget Wife Crystal X, where X is men&#x27;s us OK, and this wider presents men&#x27;s a little bit safe. Now we have been asked to answer some questions so firstly, that is, have a 1 to 1. So for 1 to 1 what were ever conditioned that if this is your domain and this is your range wonderful, wonderful Mapco only one element. OK, there&#x27;s would not be any duplicate say so. Only 1 to 1 relation then exists for the HBC that every bear having a unique element in the Metro place. 18 41 1940 and everything is unique. Nothing is coming through time. So two times one group What function? No moving her to part B. It is sent to find what off 11. So therefore, filament is clearly No. 44. The value conferred Toby 44. Now move to the park. See? It says fine F in verse 40. Think it means what we&#x27;re required. Crew were required to travel just rumors so if you re worse, it you get 40 years so it gives you the U. S. No more than the head toe. The party parties is what is f Paul have been worse for human. So what does Having more for doing from this table? Lacking word for the one is that But I think so. Right here is effort it now after authorities again for doing so. This value conforto for doing again? No, among to the next part. That is part that&#x27;s right. Yet bodies find f in worse off off. Good. Okay. What? It is when you find what is that often from this table? Because off 12. 45 Okay, so this is what four different. So really good again. Really Right after Miller&#x27;s What different And know what is afterwards for different. It&#x27;s basically again Good. Okay, hence these are the answers

Problem

Suppose gas costs $\$ 3.50$ a gallon. We make a m…

Problem 1 Medium Difficulty

The model $L=4 S$ gives the total number of legs that $S$ sheep have. Using this model, we find that 12 sheep have $L=$ __________ legs.

Answer

48 legs

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Algebra and Trigonometry

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Absolute Value - Example 1

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48 legs

Algebra and Trigonometry

Grace H.

Catherine R.

Anna Marie V.

Maria G.

Absolute Value - Example 1

Absolute Value - Example 2

James Stewart, Lothar Redlin, Saleem WatsonAlgebra and Trigonometry

Grace H.

Catherine R.

Anna Marie V.

Maria G.

James Stewart, Lothar Redlin, Saleem Watson

Algebra and Trigonometry