Question
The molar heats of fusion and sublimation of molecular iodine are 15.27 and $62.30 \mathrm{kJ} / \mathrm{mol}$, respectively. Estimate the molar heat of vaporization of liquid iodine.
Step 1
- The molar heat of sublimation is the amount of heat required to convert one mole of a substance from a solid to a gas at its sublimation point. - The molar heat of vaporization is the amount of heat required to convert one mole of a substance from a liquid to a Show more…
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The molar heats of fusion and sublimation of molecular iodine are 15.27 and $62.30 \mathrm{kJ} / \mathrm{mol},$ respectively. Estimate the molar heat of vaporization of liquid iodine.
The molar heats of fusion and sublimation of molecular iodine are $15.27 \mathrm{~kJ} / \mathrm{mol}$ and $62.30 \mathrm{~kJ} / \mathrm{mol}$, respectively. Estimate the molar heat of vaporization of liquid iodine.
The enthalpy of sublimation of iodine is $60.2 \mathrm{~kJ} / \mathrm{mol}$, and its enthalpy of vaporization is $45.5 \mathrm{~kJ} / \mathrm{mol} .$ What is the enthalpy of fusion of iodine?
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